2x^2-2/3x+20/3=0

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Solution for 2x^2-2/3x+20/3=0 equation: 



2x^2-2/3x+20/3=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We calculate fractions


2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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